7-7-53 integral cosh
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I'm going to rewrite this as negative natural log of 10 to
negative natural log of 22.
E to the Theta and definition of hyperbolic cosine is E to the
Theta plus E to the negative Theta all over 2D Theta.
So the twos are going to cancel and then I'm going to
distribute.
So we're going to get E to the two Theta plus 1D Theta.
So that's going to equal 1/2 E to the two Theta plus Theta,
negative lane 10, negative lane 2.
So we get 1/2 E to the two times negative lane 2 plus negative
lane two, and that all gets subtracted by 1/2 E to the -2
lane 10 minus LN10.
So take the -2 up into the exponent so that the E to the
LNS cancel, and we get two to the -2.
Two to the -2 is just really a fourth minus LN2.
Here's going to be minus.
Take the -2 up into the exponent.
So 10 to the -2 and the E to the LNS are going to cancel.
So 10 to the -2 is one 100th.
So we're going to get 1/2 times one 100th minus a negative makes
that a plus.
So then when we combine things we get 1/8 minus one 200th and
lane 10 minus lane two.
We can rewrite as a single lane of 10 / 2 should give me Ellen 5
S getting a common denominator here of 208 times what is 200 8
* 25 S?
We're going to get 25 two hundredths -1 two hundredths
plus Ellen of five, 24 two hundredths plus Ellen of 524,
and 200 are both divisible by 8.
So we're going to get 320 fifths plus Ellen of five.