OK, for this problem, we're going to do our definition of the absolute value of F of X minus our L has to be less than our epsilon or our error. And X -, X not has to be less than our delta. So our F of X is MX -4 M less than .03, negative .03 less than MX -4 M less than point O3. Add the four M's divide by M. It was important that M was greater than 0, which it was given, so we don't have to worry about flipping those inequality signs. So we get 4 - .03 / m less than X less than 4 + .03 / m. For the second part, we're going to have X - 4 less than delta. So negative delta less than X -, 4 less than delta. Add the four to each piece, 4 minus delta, less than X less than four plus delta. So then the left side has to equal the left side. So this side here has got to equal this side here, and the right side needs to equal the right side. So this piece here has got to equal this piece here. And we end up with delta equaling .03 / m So the interval is going to be 4 -, .03 / m, 4 + .03 / m and delta equal .03 / m.