When doing this problem, we realize that we have two X's in the first term and 2X's in the second. So we're going to do the product role and we're going to do the chain role. So we're going to take the derivative of X ^2 times the sine 6X plus the derivative of the sine 6X to the 6th power of X times the X ^2. Then we're going to add to it the derivative of X times cosine to the negative 4X plus the derivative of cosine to the -4 X times X. So the derivative of X ^2 is going to be two X sine 6X, the derivative of sine 6X. We have to use the chain rules. So we're going to bring down the six and take the exponent to one less power. Then we have to take the derivative of sine, which is cosine, and then times the X ^2. The next term, the derivative of X is just one and then the derivative of cosine to the -4 X. So we're going to bring down the -4. We're going to take it to 1 less power. Then we need the derivative of the cosine, which is negative sine, and that's all times X. So now we're going to just go through and kind of clean things up and see what we have. 2X sine to the six X + 6 X squared sine 5th X cosine X plus cosine to the -4 X negative and a negative is a positive, so plus 4X cosine to the negative 5th X sine X. And they don't have anything in common in all four terms. So that's how we're going to leave our answer.