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3-9-5
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    To find the linearization, we need to have a point and we need to have a slope. So they tell us that we want X equal π force. So to find the Y value, we're going to take F of π force. Cotangent of π force is 1. So our point is going to be π force, one. Now we need the slope. The slope is the first derivative. So the derivative of cotangent X is negative cosecant squared X. When we evaluate that at π force, we get negative cosecant squared of π force. Cosecant of π force is root 2, so we're going to square root 2 and then we're going to take the negative of it. So our slope here is going to be -2. So then linearization equals the Y value of 1 plus the slope of -2 times the quantity X - π force. If we distribute and combine like terms, we get L of X equal negative two X + 1 + π halves.