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2-4-17
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    OK, for this one, we need to remember our definition of absolute value. And we're doing the absolute value of X + 2. So it's going to be X + 2 if X is greater than or equal to -2, and it's going to be the opposite of X + 2 if X is less than -2. So when we look at this problem, when we say limit as X goes to -2 from the right of X + 7, if we're coming to -2 from the right, it's a little bit greater than -2. So we're going to use that positive X + 2 / X + 2. So then what happens is the X + 2 is canceled, leaving us just one. When we stick a -2, we get -2 + 7 * 1 or five. When we talk about the limit as X approaches -2 from the left, we have the X + 7 again. But now if we're on the left side, we're less than -2, so we're going to use the negative of X + 2 or the opposite of X + 2 / X + 2. So here when we stick in our -2, we get -2 + 7 and X + 2 / X + 2 cancels. But we still have a -1 there, so now we get 5 * -1 or -5.