2-4-17
X
00:00
/
00:00
CC
OK, for this one, we need to remember our definition of
absolute value.
And we're doing the absolute value of X + 2.
So it's going to be X + 2 if X is greater than or equal to -2,
and it's going to be the opposite of X + 2 if X is less
than -2.
So when we look at this problem, when we say limit as X goes to
-2 from the right of X + 7, if we're coming to -2 from the
right, it's a little bit greater than -2.
So we're going to use that positive X + 2 / X + 2.
So then what happens is the X + 2 is canceled, leaving us just
one.
When we stick a -2, we get -2 + 7 * 1 or five.
When we talk about the limit as X approaches -2 from the left,
we have the X + 7 again.
But now if we're on the left side, we're less than -2, so
we're going to use the negative of X + 2 or the opposite of X +
2 / X + 2.
So here when we stick in our -2, we get -2 + 7 and X + 2 / X + 2
cancels.
But we still have a -1 there, so now we get 5 * -1 or -5.