OK for this problem we need to remember our definition of the absolute value of F of X minus the limit is less than the epsilon and also the absolute value of X -, X not is less than delta. When we look at the given information, our F of X was MX plus B where M is greater than 0 IEA positive number. We also have the limit being m / 2 + b, So we're going to set that up in the absolute value MX plus B minus the quantity m / 2 + b. And that's got to be less than C because our error is C some constant, but that constant's greater than 0. So when we do this, we're going to have the constant being negative C less than MX plus b -, m / 2 -, b positive B negative B cancel less than C My goal is to solve for X. So we're going to add m / 2 to each side for all three pieces. Actually, we're going to divide by M next, and it's important that M was greater than 0 so that we don't have to worry about flipping our inequality signs. When we divide by M, we get 1/2 -, C / m less than X less than 1/2 + C / m So that's the answer to the first question. That says for what open interval does the inequality hold? So then the second part, we have our X -, 1/2, the absolute value of that less than delta. So negative delta, less than X -, 1/2, less than delta. We're going to add a half to each of the three pieces. So now we're going to take the left hand side of the one equaling the left hand side of the other. So this left hand side here is going to equal the left hand side here. And then we're going to do the same thing with the right hand side. So this right hand side here is going to equal the right hand side here. Setting those equal in solving we see that delta equals C / m.