Now find the linearization. But this time we're going to do it in a nearby integer, which is easy to evaluate. So if we know X not as 27.2, we're going to choose X to be 27, which is nearby because the cube root of 27 we know is 3. So we now have a point when X is 27, Y is 3 because the cube root of 27 is 3. Now we need a slope. So the first derivative, think of that cube root of X is X to the one third. So we're going to bring down the 1/3 and take it to the one less power. Or we get one over 3X to the 2/3 means the cube root of X and then we can square that. So 1 / 3, the cube root of 27. The cube root of 27 is 3, so 3 ^2 is 9 times the three that was already in the denominator. So 1 / 20 sevens our slope. So our linearization is our Y value 3 plus our slope of 120 sevenths times the quantity X minus our X value. When we compute that and combine like terms, we get a linearization of 120 seven X + 2 at the location of X being 27 which is near X not being 27.2.