Taking the first derivative and setting it equal to 0 and factoring, we see that we get -1 zero and one as our critical points. So now if we do our whether it's increasing or decreasing by putting in values, say choose something to the right of 1-10, five, 100, we're going to get a positive times a negative times a positive. So those are going to all be negative to the right of one at 1. Due to its odd multiplicity, it's going to change to positive. At 0. Due to its odd multiplicity, it's going to change to negative. At -1. Due to its odd multiplicity, it's going to turn back to positive. So the original function from negative Infinity to -1 is going to be increasing, from -1 to 0 it's going to be decreasing, from zero to one it's going to be increasing, and from one to Infinity it's going to be decreasing. So now if we put an H of -1, H of 0 and H of one, we get 1/3 for H of -1 and H of one. So the fact that those both are the same values tells me that those are absolute Maxis. The zero at 0 has got to be a local min because the original function is going to keep going negative in both directions. So there is no absolute minimum, but there is a local minimum at 00. So that's a local min.