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4-1-59
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    Find the critical points, domain endpoints, and local extreme for the function. So the first thing I would recommend is to multiply it out and we get X to the 7 fifths plus 2X to the 2/5. Finding the first derivative, bring down the exponent to one less power, so 7 fifths X to the 2/5 + 4 fifths X to the negative 3/5. We want to rewrite it as a single fraction. So seven X 2/5 / 5 + 4 / X to the 3/5. Multiply the top and bottom by X to the 2/5, no X to the 3/5 and the first fraction. And 2/5 + 3/5 is one whole, so seven X + 4 is in the numerator 5X to the 3/5 is in the denominator. Setting the denominator equal to 0 to figure out when the first derivative is undefined. Setting the numerator equal to 0 to find out when the first derivative is 0. So we get X = 0 and X equal -4 sevenths. If I put those on my number line. If I try something off to the right of 0, say 5-10, a million, I'm going to get a positive value at 0. The multiplicity comes from that denominator, the fact that it was to the 3/5, both of them being odd. So if I took a value and negative value and cubed it, and then I took the 5th root of a negative value, it would still be negative. So that sign is going to change from positive to negative at zero. At -4 sevenths, its multiplicity is odd, so we're going to change from negative to positive. So the original function for going positive from negative Infinity to -4 sevenths, we're increasing -4 sevenths to zero, we're decreasing 0 to Infinity we're increasing. So we know there's a local Max at -4 sevenths and a local min at 0. To find the Y values, we stick it back into the original function F and -4 sevenths is something huge and awful and it asked for it in decimal, rounded to the nearest thousandth, so we need 3 decimal places. So truly, I plugged it into my calculator and got 1.142, the local min. Plugging 0IN is pretty easy because zero times anything is 0. So that's 00 is our local min -4 sevenths 1.142 is our local Max.