We find our first derivative F prime of Theta equal negative sine Theta, so 0 equal negative sine Theta. If we divide each side by negative, we would just get 0 equaling sine Theta and that occurs at -2π and negative π given our original domain of -2π less than or equal to Theta less than or equal to -3 Pi force. So if we put -2π, negative π and -3 Pi force on a number line, if we evaluate something in between negative π and -3 Pi force like -5 Pi 6, putting it into the first derivative sign of -5 Pi 6 is a negative number, and then the opposite of a negative makes it positive. So in between negative π and -3 Pi force is going to be positive. In between -2π and negative π, if we chose something like -3 Pi halves, the sign of -3 Pi halves is positive. A positive times a negative is a negative, so in that interval it's going to be negative. The original function therefore, is decreasing from -2π to negative π and increasing from negative π to -3 Pi force. To figure out the absolute Max and mins, we actually have to find our Y values. But we know we're decreasing and then we're increasing. So we know there's a local min at negative π, and we know that there's local maxes at -2π and -3 Pi force. What we're not certain yet is which ones are the absolutes. So going back to the original function, we find the cosine Theta of -2π negative π and -3 Pi force. The absolute Max is the highest Y value, the absolute min is the lowest Y value, and then the other one that remains has to be a local Max.