We're trying to find the original function that gives us out a derivative of -12 minus cosecant squared Theta. So the original function has to be -12 Theta plus cotangent Theta plus C because the derivative of -12 Theta is -12, and the derivative of positive cotangent Theta is negative cosecant squared Theta. Given the .3 Pi force and two, we're going to put three Pi force in every time we see our Theta and two for our R of Theta. So we get 2 equaling -12 * 3 Pi force, which reduces to -9 Pi cotangent of three Pi force is -1 plus our constant C. Add the one across, add the -9 Pi. We get 3 + 9 Pi for our C, so putting it back in we get R Theta equal -12 Theta plus cotangent Theta plus 3 + 9 Pi.