We're told that F of X equal log base three of X is this graph here, so the +4 shifts the entire thing up by 4. We could also think about solving this. If we have y -, 4 equaling log base three of X, then we know that three to the Y - 4 power would equal X. So we can make ourselves a teacher and we would put in values for Y, not for X because it was X equal. We always want what makes the exponent go to 0. So we're going to put four, and then we're going to put a couple that are smaller and a couple that are bigger. SO2345 and six. If we stuck 2IN, we'd get three to the 2 -, 4 or three to the -2, which would be 1/9. If we stick 3IN, we'd get three to the 3 -, 4 or three to the -1 or one third. I didn't leave myself enough room, so 1/3 was for three. If we put four in three to the 4 - 4, which would be 3 to the zero, and anything to the zero is 1. If we put five in three to the 5 - 4, three to the first, which is just three. If we put six in three to the 6 -, 2 three, oops, three to the 6 - 4, which would be 3 ^2 or 9. So what's the graph of the two functions? We know this was the original and we went up by 4. The vertical asymptote. We can see that we're getting closer and closer and closer to X equaling 0. As the YS get smaller, the XS get smaller, but it's always going to be 0. The domain is going to be 0 to Infinity and the range is going to be all real numbers because I can put in a negative number in this exponent. We have three to some exponent. Whatever the exponent is, it's still going to come out as positive.