In this problem, we're going to use the elimination method. So we're going to take that top equation and multiply it all the way through by two so we can get additive inverses on that y ^2 term. So when we add and we get 9 / X ^2, the 2 / y ^2 cancel equaling 9, cross multiply 9 X squared equal 9, divide by 9 and then square root remembering positive and negative so X equals positive -1. Now when we stick one into one of the original equations, 1 ^2 is just one -1 ^2 is also one. So 3 + 1 / y ^2 equal 5. We subtract the three and we get 2. So cross multiply 1 equal 2 / y or one equal 2 * y ^2 / 2 one half equal y ^2. Take the square root remembering positive and negative, and then we're going to rationalize that. So Y equal positive, negative root 2 / 2. So our four points are going to be 1 root 2 / 2, negative 1, root 2 / 2, one negative root 2 / 2, and -1 negative root 2 / 2.