When looking at this problem, we have the minute hand of a clock being 10 inches long. So somewhere we have 10 inches long, IE the radius. And we want to know how far does the tip move in 35 minutes. So I'm going to estimate right about there. So what we're really looking for is how far the tips moving or the arc length. So the first thing we have to remember is what's the formula for arc length? Well, if we think about S being the arc length, we don't want the full circle, we want a portion. We want Theta out of the full circle. Let's do this in radians, so Theta out of 2π. And then the formula for circumference of a circle is just 2π R So remember this is in radians. It does matter. If we simplify this equation up, we get S equals Theta times R. Well, we already know the R. The R is just 10 inches. The Theta we don't know quite yet because we don't have it in radiance, but we do know it went 35 minutes. So the easiest way to do this one, I think, is to think about 35 minutes and multiply it by an equivalent of one. Well, we know 60 minutes is one full circle, and we also know that 2π radiance is one full circle. So now we can convert this. 35 and 60 are each divisible by 5, so we would get 7 * 2π / 12 radians. The minutes are going to cancel and two and the 12 are each divisible by two. So I'm going to get 7 Pi 6th radians for simplified. Now going back to that S equal Theta R equation, S equal the Theta now is in radians 7 Pi six. Our R was given us 10, so 6 and 10 are both divisible by two. So we're going to get 35 Pi thirds inches. I didn't show it, perhaps I should have. Here's when we cancel here we get our Theta times our R, which is going to give us our inches as our unit. SO35, Pi, thirds, inches. And in this problem they want you to put it as a decimal. I assume that you can figure that out on your calculators.