When doing this problem, I would do it in steps. So if we thought about Y equaling sine X to start, we know that our sine graph goes starts at the origin, it goes for forever and it looks something like this. So with this new one, we're going to figure out the amplitude. The amplitude is always the absolute value of the number right in front of the sine or cosine. So in this case 4, we're going to figure out our period, our period for sine. Regular sine is 2π and the new. Is always 2π divided by the number that's multiplied by the X, in this case 2π thirds. There is going to be no phase shift, and the way we can figure that out is if we set the parenthesis equal to 0, we would get zero. Our vertical translation, however, is going to be that number three. Now, if this doesn't look like something you're used to, you could think about rewriting this original equation as Y equaling -4 sine 3X plus a three at the end, because that's where our vertical translation usually is. So now let's put it all together. If we're going to graph this, our sine is going to still start at the origin because we didn't have a phase shift. It's a -4. So it tells us we're going to go down 4 instead of up four. We're going to get through an entire phase in 2π thirds distance. Now this is all without the vertical translation, and it would keep going for forever in both directions. OK. So now we have to actually put in our vertical translation, and our vertical translation is 3. So instead of it being at -4 here, we're going to be now at -1 Instead of being at 0 here, we're going to be at 3:00, and this zero is going to go to three, and this zero is going to go to three. And then instead of being at 4:00, we're going to be up here at 7:00. Now, we still need to find our five key points, but this is what our graph's going to look like, our five key points. There are lots of ways to do this, but one method would be to take that. And divide by 4. If I divide by 4, it's the same thing as multiplying by a fourth. So the two and the four were reduced to 2:00. So we get PI6. So if I start at my beginning and add Pi 6, and if I do this four times I should get at my ending. Pi 6 + π six is going to be two Pi 6 which would reduce to π thirds. Two Pi 6 + π six would be 3 Pi 6, which is π halves. And then three Pi 6 + π six is 4 Pi 6, which is 2π thirds, which is what I expected because it needed to be at our end location. So at zero, our next location would be Pi 6. So this point here is going to be Pi six -1 This next location is going to be π thirds three. This next location is going to be π halves 7. And the last location on this one period is going to be 2π thirds three. I guess I should put on our starting point which is 03.