1-3-67 difference quotient
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When doing this kind of problem, we have to find what F of X + H
is.
We have to find out what F of X is, and then we have to subtract
and divide by H.
So frequently, if students don't remember how to do this, I
suggest starting with numbers.
If I asked you what F of one is, could you find it?
You'd put in one every time you saw your unknown, so 1 - 7 + 4
would be -2.
If I asked you what F of 0 is, could you find it?
0 ^2 - 7 * 0 + 4.
If I asked you for F of five, 5 ^2 - 7 * 5 + 425 - 35 negative
10 + 4 negative 6.
So then I switch concepts and I say, well, what if I asked for F
of A?
Could you find F of A?
And hopefully you see the pattern and you put in A every
time you see the unknown.
And if I ask for F of T, you would tell me we put in T every
time we see the unknown.
And then I ask F of 5B say we'd put in 5B every time we see the
unknown.
So then after that, oops, it was there.
Then after that I would ask what is F of X + H?
And hopefully after doing a bunch of examples, you'd say X +
H ^2 -, 7 X plus H + 4.
So then we would distribute and we'd get X ^2 + 2 XH plus H ^2
-7 X -7 H +4.
So now we're going to put it all together.
And to put it all together, we're going to say, let's see, F
of X + H -, F of X all over H So we just found that F of X + H,
that whole thing X ^2 + 2 XH plus H ^2 -, 7 X -7 H +4, that
whole thing is just F of X + H Now we're subtracting F of X.
Well, that was given as X ^2 -, 7 X +4 and that whole thing has
got to be over H So now we can see the X ^2 and minus X ^2 is
going to cancel.
We get 2 XH plus H ^2, the -7 X and the minus.
The negative minus the negative made it positive.
So the seven X -7 X and positive 7X are going to cancel.
We get -7 H and then the +4 and the -4 are going to cancel all
over H So now we can see that every single term has an H in
it.
So if we factor out an H, we'd get two X + H - 7 all over H and
then H / H is going to cancel.
So our final answer is just going to be two X + H -, 7.