We need to make sure to isolate the root by itself on one side. So sqrt X + 7 = X -, 5. Now to get rid of a square root. Once it's all by itself, or actually any root, once it's all by itself, we're going to raise it to whatever the index is to that power. So sqrt X + 7, we could really think of X + 7 to the one half. So to get rid of that 1/2, we're going to square it. And if I square one side, I have to square the other. So we could also think of how we'd get rid of a square root is to square it. So when I square a square root, we get X + 7 left on the left side. On the right side, we're going to actually have to foil it out X ^2 -, 10, X plus 25. Now we're going to subtract to get everything on one side with zero on the other. So X ^2 -, 11 X plus 18. Now 2 numbers that multiply to give me 18 but add to give me -11. Those two numbers are going to be -2 and -9. So once we have this set up, we're going to set each of those factors equal to zero X -, 2, X -9 So X equal to and X equal 9. Now remember, we absolutely have to check these. We have to see if putting these back into the original will work. So sqrt 2 + 7 + 5 does that equal to. Well, sqrt 9 is 3, so does 3 + 5 equal 2? And the answer is obviously no, 8 does not equal 2, so that one doesn't work. Now we have to check the other one. Sqrt 9 + 7 + 5 equaling 9, so 9 + 7 sqrt 16 Sqrt 16 is 4/4 plus five does indeed equal so 9 equal 9. So our answer is going to be there's one solution, it's X equal 9 X equal 2 is what's called an extraneous solution. Extraneous means it's an extra solution that doesn't actually work.