Solve using the elimination method. The first thing I would recommend is to get rid of your fractions by multiplying through by the common denominator. So on this first one, the common denominator is 10. So if I said 10 * 2 X over 5 + 10 * y / 2 equal 10 * 2, those 10s and the fractions are understood to be over one. SO5 goes into Ten 2 * 2 * 2 X leaves us, 4X2 goes into ten, 5 * 5 * y gives US5Y, and then 10 * 2 is 20. In the second equation, we're going to multiply everything through by 6. So if I multiply by six 6 / 1 times X / 2 - 6 / 1 * y / 6 = 6 * 5 S, now we get 2 going into six three times, so 3X the sixes and this next one cancels, so three X -, y equal 30. The first equation once again turned into 4X +5 Y equal 20. To do elimination, we want to get coefficients to be the same. So if we looked at the YS, if I multiplied the red equation by 5, I'd get 15 X -5 Y equaling 150. The blue equations going to say 4X +5 Y equal 20. The reason to do that is now when I add those two equations, the YS have additive inverses, one's a -5 Y and one's a +5 Y. So when we add those, those are going to cancel and we're going to get 19X equaling 170. So X is 170 nineteenth. Now I personally don't really want to substitute that in because I think that might turn into some really nasty numbers. So I'm going to go back to these original 2 equations, and this time I'm going to eliminate the X's. I'm going to multiply this top one by three. If I multiply the top one by three, I get 12X plus fifteen y = 60. And if I multiply this bottom one by a -4 negative 4, so I get -12 X plus 4Y equaling -120. When I add these, the XS cancel and I get 19 Y equaling -60 or Y equal -60 nineteenths. So this is really a point. It's the .170 nineteenths -60 nineteenths. The fact that we have a solution means that it's consistent, and the fact that it's a single point means it's dependent.