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3-2-17 substitution and elimination
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    When doing this problem using the substitution method, we want to solve one of these equations. For one of the variables I, we usually look for a one or -1 coefficient. So this bottom one we're going to solve for Y. So we're going to get two X -, 6 equal. Yi added the negative Y to the right side, and I subtracted 6 to the other. Once we have this, we're then going to substitute it into the other. So two X + 4 instead of Y. We're going to put in what Y equaled, which is 2 X -6 equaling -2. Now we're just going to do distribution. 2X plus eight X -, 24 equal -2, so 10X -24 equaling -2. Add the -24 to each side. So 10 X equal 22 / 10 X equal 22 tenths, which will reduce to 11 fifths. Now, 11 fifths isn't very easy to substitute in. SO I think that we shall take this top equation. Remember again, we're trying to do substitution, and I can see that that entire top equations divisible by two. So let's do X + 2 Y equaling -1 taking that top equation, dividing it all by two. So then if I solve for XI get X equaling -1 - 2 Y going to substitute that into the other equation. So 2 * -1 - 2 Y equaling. Wait a SEC, I lost myself 2 * -1 - 2 Y minus Y equaling 6 doing the distribution property -2 - 4 Y minus Y equal -6 negative 2 - 5 Y equaling -6 Add the -2 to each side so -5 Y equaling -4 So oh, I switched that from a +6 to a negative. Hold on a SEC. Go back and put it as a six. Adding the -2 we get eight -5 Y equaling 8 divide. So we get Y equaling -8 fifths. Now substitution is an OK method, but I actually think elimination is easier. So let's go ahead and do this exact same problem with elimination. Elimination says we want to get positive coefficients for one variable, negative for the other, IE additive inverses. So if we left that top equation exactly the way it is, and we multiplied the second equation by a -1, we get -2 X plus Y equaling -6. When we add those two equations together, we'd get 5 Y equaling -8 Y equal -8 fifths. Now going back to do the X, we can see that if we multiply that second equation through by a four, the whole equation, so it's going to turn into eight X -, 4 Y equaling 24. When I add that the YS are going to cancel, we get 10X equaling 22. So X = 22 tenths, which reduces to 11 fifths. So I just showed the substitution method and the elimination method. Remember to always give our answer as an ordered pair in alphabetical orders, in this case the X and then the Y, because there's a solution that's consistent, and because it's a single point, they're independent of each other.