OK, for this problem, we're going to graph all four equations. So we're going to have three Y less than or equal to negative X + 9, and we divide by three, we get Y less than or equal to -1 third X + 3. So we're going to go up three, and then we're going to go down one and to the right three. So down one and to the right three, down one and to the right three. For the next equation, we're going to take that 3X across. So we're going to go up nine, and now we're going to go down 3 and over one, down 3 and over one, down 3 and over one. We want Y less than or equal to. So we're going to shade below that line. On the first line, we wanted Y less than or equal to also. So we're going to shade below on that line. And then we have X greater than or equal to 0X greater than or equal to 0. If we recall X = 0 as a vertical line, so we're going to shade off to the right of that vertical line, and then the last one says Y greater than or equal to zero. Y = 0 is a horizontal line, so we need above. So the place that all four of those is true is in that yellow shaded area.