6-3-27 complex fraction
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When doing this kind of problem, we're going to look at just the
numerator portion by itself to start.
So our thought ought to be, is the denominator a monomial?
And Z + d is 2 terms, so it's not a single term.
There's nothing we can factor out of it other than we could
pull out A1 as a placeholder.
We might not need to do that, but it might help to see that
now it is a monomial.
The second term currently is a monomial also because it is a
single term in the denominator.
So now when I look for the common denominator between the
two, they have to be exactly the same.
Z + d is not exactly the same as Z so I actually need the common
denominator to be Z * Z + d And if I look at this first one
right here, I need to multiply that by AZ on top and bottom to
get this new common denominator.
So if I multiply by AZ on top and AZ on bottom, that would
give me the new common denominator.
So I'd get one time Z or plain old Z on top.
Then we have minus and we have this new common denominator of Z
* Z + d and the second term had A1 over Z.
Well, right, there's the Z.
But I need AZ plus D in the denominator also.
So I'm going to have to multiply by Z + d in the top and Z + d in
the denominator in order to get the common denominator.
1 * Z + d is going to be Z + d So if we keep going with this,
we're now going to have AZ minus the quantity Z + d in the
numerators all over Z * Z + d If we distribute out the negative,
we get Z -, Z -, d / Z * Z + d or negative d / Z * Z + d Now
that's just the numerator.
So that's this top part.
Now we need to divide that by D so I have negative d / Z * Z + d
/ d So if I think about dividing by, that's really the same thing
as multiplying by one over its reciprocal.
So if we have this and we multiply by 1 / d, now
everything's still a monomial because everything is just
either in parentheses or straight multiplication or
division.
So this D in the numerator and this D in the denominator are
actually going to cancel because we know anything over itself
reduces to 1.
So once those two cancel, we get a final answer of -1 / Z * Z +
d.