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3-2-15 substitution
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    Solve using the substitution method. So we're going to look for a single variable with A1 or -1 and we can see that the top equation has the Y with A1 in front of it. So we're going to add the 7X to the other side. So y = 7, X plus 57. We're going to do the substitution method, so we're going to substitute it into the other equation. So nine X + 18 instead of Y, we're putting in that seven X + 57 equaling 81. So nine X + 120, six X + 18 * 57 and I am grabbing my handy dandy calculator 1026 equaling 81. When we combine like terms, we get 135X equaling 81 -, 1026, so -945. Then we divide each side by that 135 and we get -7. Once we get X, we can plug it right back into the Y equal equation. So 7 * -7 + 57, so Y equal -49 + 57 or Y equal 8. So it's going to be the point negative 7-8. The fact that it's a point means they're consistent because there's at least one equation, and the fact it's a point also means they're independent. One line is independent of the other.