3-2-15 substitution
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Solve using the substitution method.
So we're going to look for a single variable with A1 or -1
and we can see that the top equation has the Y with A1 in
front of it.
So we're going to add the 7X to the other side.
So y = 7, X plus 57.
We're going to do the substitution method, so we're
going to substitute it into the other equation.
So nine X + 18 instead of Y, we're putting in that seven X +
57 equaling 81.
So nine X + 120, six X + 18 * 57 and I am grabbing my handy dandy
calculator 1026 equaling 81.
When we combine like terms, we get 135X equaling 81 -, 1026, so
-945.
Then we divide each side by that 135 and we get -7.
Once we get X, we can plug it right back into the Y equal
equation.
So 7 * -7 + 57, so Y equal -49 + 57 or Y equal 8.
So it's going to be the point negative 7-8.
The fact that it's a point means they're consistent because
there's at least one equation, and the fact it's a point also
means they're independent.
One line is independent of the other.