To start this problem, we're going to factor all of the denominators. So X ^2 - 6 X +8 is X - 2 X -4 X squared minus nine, X + 20 is X - 4 X -5 X squared minus seven, X + 10 is X - 2 X -5 and X ^2 + 2 X -35 is X - 5 X +7. So just looking at the numerator, getting a common denominator would be X - 2 * X - 4 * X - 5. So that first term needs an X - 5 on the top and the bottom. The next term needs to have an X -, 2 multiplied on both the top and the bottom. If we're looking at the denominator, our common denominator there is going to be X -, 2 X -5 X +7. So the first term in the denominator has to be multiplied in the top and the bottom by X + 7, and the second one, both the top and the bottom have to get multiplied by X -, 2. So now we're going to distribute those numerators out. So if I have 2 * X and 2 * -5 that's going to give me two X - 10 + 2 * X two X 2 * -2 negative 4. The denominator stays the same and do the same thing in the bottom. So 2 * X two X 2 * 714 two times X again 2 X 2 * -2 -, 4 once again keeping that denominator what it had been. So now if we combine like terms, we going to get four X -, 14 in the top. And we realized that both 4X and 14 are even. So we could factor out A2 to get two times the quantity two X -, 7 denominator still says the same. Now in the bottom part, when we combine our like terms here, we get four X + 10. Once again, 4X and 10 are both even. So we're going to pull out A2 and that's going to give us two times two X + 5. I'm going to flip it so that we can multiply instead of divide. So that X -, 2, X -5 and X + 7 are going to go on top. Now the X -, 2 here and the X -, 2 here are going to cancel. The two here and the two here are going to cancel. And finally the X -, 5 here and the X -, 5 here are going to cancel. So we're going to get two X - 7 * X + 7 / X - 4 times two X + 5.