When working this problem, we need to factor everything so we can figure out a common denominator. So we have six C - 1 / Z + 5 and Z -, 8 -, Z - 16 / Z + 5 Z -5. So our common denominator here is going to be Z + 5 Z -8 and Z - 5. The reason is we need every single term that we have listed, and we need to make sure that anything that's listed in both terms we only write down one time. So the Z + 5 was in each term. So we write it one time and then we write everything else that wasn't there. So in this first term, we have to realize that we didn't have AZ -5 on top. So I'm going to multiply 6 Z -1 * Z -, 5. In the second term, we can see we didn't have AZ -8 in the bottom originally, so we're going to write it on top. So now we need to foil out those tops. So we get six C ^2 -, 30 Z minus C + 5 all over that common denominator. Then we get Z ^2 -, 8 Z -16 Z plus 128 all over that common denominator. So now that we have a common denominator, we're going to combine the numerators. So we have 60 ^2 and 30 negative 30, and -1 is going to give us a negative 31 Z +5. Now we're subtracting, so it's minus C ^2. If we have a -8 negative 16, that's going to be a -24, but it was a -, a negative 24. So that turns into a + 24 Z. And then minus the 128 Z + 5 Z -8, Z -5 are still in the bottom. So now six C ^2 -, C ^2 is going to give us five Z ^2, a negative 31 and a +24 is going to give us a -7 Z and then a +5 and a -128 is going to give us a -123. Now we actually need to see if that five Z ^2 - 7 Z -123 will factor and if it does then we could reduce it. 5 * -123 negative 5 carry one -615 so six negative 6/15, 1:00 and 6:15. Three and three goes into six twice two O 5. We're looking for something that'll multiply to give us that middle number of -7. So let's see then if we take out a three, five will come out with 12315, will come out with 41, 15 and 41. That's not going to do it. So there isn't going to be anything that'll give us the -7 So that's going to be our final answer.