When doing this problem, we need to get rid of the innermost parentheses first. So we're going to distribute by -4 and get -12 + 4 X. On the other side, we're going to get rid of the innermost parentheses 1st and get 10 X -5. Now within the brackets, we're going to combine our like terms. So we get -5 + 4 X and then the other bracket we're going to get 10X plus one. Then we're going to distribute the two -10 plus 8X, going to distribute the two again on the other side, 20X plus two. Now combining our like terms -10 + 8 X -1 would give us eight X -, 11. On the other side, we combine our like terms and we get 20 X -19 getting all the XS on the left side. So I'm going to subtract the 20X and get -12 X. I'm going to add the -11 or add 11 to each side. So I get -8 going to divide by -12 when I divide by -12. We have to remember we flip the inequality sign whenever we divide or multiply by a negative. So X less than or equal to -8 negative 8 / -12 that reduces to X less than or equal to 2/3. So it's the set of all XS such that X less than or equal to 2/3.